This section will give you several different recipes for bruschetta toppings. They range from sweet to sweet n' savory, to savory. Cut a clove of garlic in half, and rub it over the oily side of the toasted bread slices. Finish off with a drizzle of olive oil and a sprinkle of salt and/or pepper. Spread some gorgonzola cheese over the oily side of each bread slice. Bake, broil, or grill the bread, cheesy-side-up for a few more minutes until the cheese has melted. Transfer the bruschetta slices to a platter, and drizzle each slice with honey. Serve immediately.  You will need about 8 ounces (225 grams) of gorgonzola cheese and 3 tablespoons of honey. For an added crunch, add some chopped walnuts or pecans on top. Spread 2 tablespoons of ricotta cheese over the top of each bread slice. Add 1 tablespoon of marmalade to each slice and serve. Spread some cream cheese over the bread slices, then drape a slice of salmon over each one. Finish off with a sprinkle of dill. Spread some goat cheese onto the toasted bread slices. Place a slice of prosciutto over the cheese. Add two, thin peach slices. Finish off with a drizzle of olive oil and a pinch of sea salt. Serve immediately. In a small bowl, combine 8 ounces (225 grams) of ricotta cheese and the zest of 1 lemon. Add salt and pepper to taste and spread over the toasted bread slices. Finish off with a drizzle of honey and a sprinkle of thyme. Serve while it is still warm. Slice enough strawberries to cover the tops of the toasted bread slices. Generously sprinkle the strawberries with sugar. Turn on the broiler, and heat the bruschetta for about 2 minutes, or until the sugar caramelizes.
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One-sentence summary -- Prepare some toasted slices of baguette, then add your desired topping. Try a simple seasoning of garlic, olive oil, and salt. Use a gorgonzola-honey topping if you like the savory-sweet. Use ricotta cheese and marmalade for another savory-sweet combination. Use a classic combination of salmon and cream cheese. Try some prosciutto, peaches, and goat cheese for a more unique flavor. If you want something zesty, give ricotta cheese and lemon a try. If you have a sweet tooth, try strawberries and sugar.

Article: This method covers problems in the form logb⁡(x)logb⁡(a){\displaystyle {\frac {\log _{b}(x)}{\log _{b}(a)}}}. However, it does not work for a few special cases:  The log of a negative number is undefined for all bases (such as log⁡(−3){\displaystyle \log(-3)} or log4⁡(−5){\displaystyle \log _{4}(-5)}). Write "no solution." The log of zero is also undefined for all bases. If you see a term such as ln⁡(0){\displaystyle \ln(0)}, write "no solution." The log of one in any base (log⁡(1){\displaystyle \log(1)}) always equals zero, since x0=1{\displaystyle x^{0}=1} for all values of x. Replace that logarithm with 1 instead of using the method below. If the two logarithms have different bases, such as log3(x)log4(a){\displaystyle {\frac {log_{3}(x)}{log_{4}(a)}}}, and you cannot simplify either one into an integer, the problem is not feasible to solve by hand. Assuming you did not find any of the exceptions above, you can now simplify the problem into one logarithm. To do this, use the formula logb⁡(x)logb⁡(a)=loga⁡(x){\displaystyle {\frac {\log _{b}(x)}{\log _{b}(a)}}=\log _{a}(x)}.  Example 1: Solve the problem log⁡16log⁡2{\displaystyle {\frac {\log {16}}{\log {2}}}}.Start by converting this into one logarithm using the formula above: log⁡16log⁡2=log2⁡(16){\displaystyle {\frac {\log {16}}{\log {2}}}=\log _{2}(16)}. This formula is the "change of base" formula, derived from basic logarithmic properties. Remember, to solve loga⁡(x){\displaystyle \log _{a}(x)}, think "a?=x{\displaystyle a^{?}=x}" or "What exponent can I raise a by to get x?" It's not always feasible to solve this without a calculator, but if you're lucky, you'll end up with an easily simplified logarithm. Example 1 (cont.): Rewrite log2⁡(16){\displaystyle \log _{2}(16)} as 2?=16{\displaystyle 2^{?}=16}. The value of "?" is the answer to the problem. You may need to find it by trial and error:22=2∗2=4{\displaystyle 2^{2}=2*2=4}23=4∗2=8{\displaystyle 2^{3}=4*2=8}24=8∗2=16{\displaystyle 2^{4}=8*2=16}16 is what you were looking for, so log2⁡(16){\displaystyle \log _{2}(16)} = 4. Some logarithms are very difficult to solve by hand. You'll need a calculator if you need the answer for a practical purpose. If you're solving problems in math class, your teacher most likely expects you to leave the answer as a logarithm. Here's another example using this method on a more difficult problem:  Example 2: What is log3⁡(58)log3⁡(7){\displaystyle {\frac {\log _{3}(58)}{\log _{3}(7)}}}? Convert this into one logarithm: log3⁡(58)log3⁡(7)=log7⁡(58){\displaystyle {\frac {\log _{3}(58)}{\log _{3}(7)}}=\log _{7}(58)}. (Notice that the 3 in each initial log disappears; this is true for any base.) Rewrite as 7?=58{\displaystyle 7^{?}=58} and test possible values of ?:72=7∗7=49{\displaystyle 7^{2}=7*7=49}73=49∗7=343{\displaystyle 7^{3}=49*7=343}Since 58 falls between these two numbers, log7⁡(58){\displaystyle \log _{7}(58)} has no integer answer. Leave your answer as log7⁡(58){\displaystyle \log _{7}(58)}.
Question: What is a summary of what this article is about?
Check for negative numbers and ones. Convert the expression into one logarithm. Calculate by hand if possible. Leave the answer in logarithm form if you cannot simplify it.