Summarize the following:
In most cases, the color paint code in Ford vehicles is written on a manufacturer’s label located on the driver's side front door panel, usually along the rear edge of the door. If you open your door and look along the side of the door, towards the bottom you should see a manufacturer's label. This will contain the color code.  These labels are rectangular and may be printed with a Ford watermark and/or a patterned background. They typically say “MANUFACTURED (or MFD.) BY FORD MOTOR CO. (or COMPANY)” at the top. Modern manufacturing labels typically have a barcode printed on them, while older examples may not. The majority of Fords will have the manufacture's label on the front door panel. However, it may be on the rear part of the front driver’s side door jamb. Open the front car door on the driver's side. Look at the small ridge around the doorframe on the inside of the car, usually blocked when the door is closed. The manufacturer's label may be towards the bottom of the jamb, on the rear side (closer to the back of the car). Once you've found the manufacturer's label, you can use this to locate the color code. The color code is found below the bar code and is usually marked by 2 characters, which can be either numbers or letters. The 2 digits are listed above or next to the words "exterior paint colors." For example, if you saw the letters "PM" written above "exterior paint colors," this would mean the color code is PM. Some Ford color codes—especially for older vehicles—may be longer than 2 characters. They may also consist of a mixture of letters and numbers. For example, the color code for the shade “Maroon,” used on the 1964 Ford Fleet, is MX705160.

summary: Look on the driver's side front door panel. Check the driver's side front door jamb. Locate the color code on the manufacturer's label.


Summarize the following:
Suppose, as a different problem, that you know two sides and need to solve an unknown angle. You are given that side A is 10 inches long, side B is 7 inches long, and angle α{\displaystyle \alpha } is 50 degrees. You can use this information to find the measurement of angle β{\displaystyle \beta }. Set up the problem as follows:  Asin⁡α=Bsin⁡β{\displaystyle {\frac {A}{\sin \alpha }}={\frac {B}{\sin \beta }}} 10sin⁡50=7sin⁡β{\displaystyle {\frac {10}{\sin 50}}={\frac {7}{\sin \beta }}} sin⁡β=7sin⁡5010{\displaystyle \sin \beta ={\frac {7\sin 50}{10}}} sin⁡β=7∗0.76610{\displaystyle \sin \beta ={\frac {7*0.766}{10}}} sin⁡β=0.536{\displaystyle \sin \beta =0.536} In the above example, the law of sines provides the sine of the selected angle as its solution. To find the measure of the angle itself, you must use the inverse sine function. This is also called the arcsine. On a calculator, this is generally marked as sin−1{\displaystyle \sin ^{-1}}. Use this to find the measure of the angle. For the example above, the final step is as follows:  sin⁡β=0.536{\displaystyle \sin \beta =0.536} β=arcsin⁡0.536{\displaystyle \beta =\arcsin 0.536}  β=32.4{\displaystyle \beta =32.4}. Suppose you are told that angle α=30 degrees{\displaystyle \alpha =30{\text{ degrees}}}, angle β=50 degrees{\displaystyle \beta =50{\text{ degrees}}}, and side C, which connects them, is 10 inches long. Find the measurement of all sides and angles for the triangle.  First, you should recognize that you do not yet have enough information for the sine rule to apply. The sine rule requires that you have at least one pair with an angle that opposes a known side. However, you can calculate the third angle of this triangle using simple subtraction. All three angles add up to 180 degrees, so you can find angle γ{\displaystyle \gamma } by subtracting: γ=180−α−β=180−30−50=100{\displaystyle \gamma =180-\alpha -\beta =180-30-50=100}  Now that you know all three angles, you can use the sine rule to find the two remaining sides. Solve them one at a time:  Csin⁡γ=Bsin⁡β{\displaystyle {\frac {C}{\sin \gamma }}={\frac {B}{\sin \beta }}} 10sin⁡100=Bsin⁡50{\displaystyle {\frac {10}{\sin 100}}={\frac {B}{\sin 50}}} 10sin⁡50sin⁡100=B{\displaystyle {\frac {10\sin 50}{\sin 100}}=B} 10∗0.7660.985=B{\displaystyle {\frac {10*0.766}{0.985}}=B} 7.78=B{\displaystyle 7.78=B}   Thus, side B is 7.78 inches long. Now solve for the final remaining side.  Csin⁡γ=Asin⁡α{\displaystyle {\frac {C}{\sin \gamma }}={\frac {A}{\sin \alpha }}} 10sin⁡100=Asin⁡30{\displaystyle {\frac {10}{\sin 100}}={\frac {A}{\sin 30}}} 10sin⁡30sin⁡100=A{\displaystyle {\frac {10\sin 30}{\sin 100}}=A} 10∗0.50.985=A{\displaystyle {\frac {10*0.5}{0.985}}=A} 5.08=A{\displaystyle 5.08=A}   Side A, therefore, is 5.08 inches long. You now have all three angles, 30, 50 and 100 degrees, and all three sides, 5.08, 7.78, and 10 inches.
summary: Solve for an unknown angle. Use the inverse function if needed to find the angle. Solve a problem with incomplete information.